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enot [183]
4 years ago
7

PLEASE HELP ME!!!!!!!

Computers and Technology
2 answers:
IRISSAK [1]4 years ago
8 0

Answer:

Hyperlink

Explanation:

A hyperlink is an icon, word, phrase, or image that can be clicked on to jump to a new document or a new section within the current document.

Text hyperlinks are often blue and/or underlined but this is optional but is the convention.

A hyperlink may point to a whole document or to a specific element within a document. A text with hyperlinks is called hypertext and text that is linked from is called anchor text.

vitfil [10]4 years ago
5 0
It is probably a hyperlink, but it could be an action.
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Identify a characteristic of electronic meeting systems.
densk [106]

Answer:

The correct answer to the following question is an option (b).

Explanation:

Desktop conferencing is the feature of the electronic meeting system.

An EMS or electronic meeting system is an application that gives us the facilities of problem-solving and making decisions for that problem within a group, and it also provides the best feature of web conferencing, and the desktop conferencing by which we can chat and tells our problem in the group or a person.

8 0
4 years ago
Consider a multidimensional array A stored in row-major order with 22 rows and 6 columns whose subscripts start at 0. If each el
siniylev [52]

Answer:

Option c is the correct answer for the above question.

Explanation:

  • If the array will store in row-major order, then it will be a store like the first row, then second row and then third row.
  • If the user wants to conclude the address of the A[3,5], then the address of the A[3,5] will be 184.
  • It is because the 3 states the row number and the 5 states the column number.
  • The above question states that every value take 8 bit. and there are 4 rows from 0 to 3 and 6 column (0 to 5) for every row (except the fourth rows because it takes 5 columns from 0 to 4) before the A[3,5].
  • So there are 23 value before A[3,5] which are as-- [00,01,02,03,04,05][10,11,12,13,14,15][20,21,22,23,24,25][30,31,32,33,34].
  • So when every value takes 8 bit then 23 value takes 184 bits(23*8).
  • So the address of A[3,4] is 184.
  • Hence option c is the correct and the other is not because of 184 stated from the c option only.
4 0
3 years ago
Negative numbers are encoded using the __________ technique. a. two’s complement b. floating point c. ASCII d. Unicode
OLEGan [10]

Negative numbers are encoded using the two’s complement technique. Two's complement is used to encode negative numbers.

Option  A is correct .

<h3>What method does the in data type use to store negative numbers?</h3>

Most implementations you're likely to encounter store negative signed integers in a form known as two's complement. Another important way of storing negative signed numbers is called one's complement. The one's complement of an N-bit number x is basically defined as x with all bits inverted.

<h3>What is encoding method?</h3>

An encoding technique is the application of established industry conventions to a coded character set to create a coded character scheme. Such rules determine the number of bits required to store the numeric representation of a given character and its code position in the encoding.

Learn more about two complement technique encoding :

brainly.com/question/26668609

#SPJ4

5 0
1 year ago
Which type of input devices used in big hero 6 movie
Maslowich

The  Input Devices Used in Movie Big Hero are:

  • A joystick
  • medical robot
  • Armored exoskeleton
  • Jet-boots.

<h3>What are input device?</h3>

This is known to be a is a piece of instrument that helps gives or provide data to any information processing system.

Note that the Input Devices Used in Movie Big Hero “6”  are  a medical robot made by by Tadashi Hamada., Armored exoskeleton and others.

Learn more about input device from

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7 0
2 years ago
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
4 years ago
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