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makkiz [27]
4 years ago
15

Please help with the problem below! Thank you

Mathematics
2 answers:
Gwar [14]4 years ago
6 0

Answer:

d \le -3

Step-by-step explanation:

The given inequality is;

\frac{d-3}{10} \ge \frac{2d+3}{5}+\frac{d+3}{3}

Clear the fraction by multiply through by 30;

3(d-3) \ge 6(2d+3)+10(d+3)

Expand;

3d-9\ge 12d+18+10d+30

Group like terms;

3d-12d-10d \ge 18+30+9

-19d \ge 57

Divide through by -19 and reverse the sign.

d \le -3

777dan777 [17]4 years ago
4 0

Answer:

Choice A is correct. d ≤ -3 is the answer.

Step-by-step explanation:

 We have given an inequality:

\frac{d-3}{10}\geq \frac{2d+3}{5}+\frac{d+3}{5}

We have to solve the inequality.

\frac{d-3}{10}\geq \frac{3(2d+3)+5(d+3)}{15}=\frac{6d+9+5d+15}{15}=\frac{11d+24}{15}

\frac{d-3}{10}\geq \frac{11d+24}{15}

15(d-3)\geq10(11d+24)

15d-45\geq110d+240

15d-110d ≥ 240+45

-95d ≥ 285

d ≤ -3 which is the answer.

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Answer:

<em>u</em> = 7.21

Step-by-step explanation:

The magnitude of <em>u</em> is just the distance between the two points. The coordinates of the left-most point are (-2,-8) and the coordinates of the right point are (4, -4). I'm assuming the x coordinates here because we don't actually know the scale.

Ok so from these points, you can draw a triangle (u can see it in the attached file).

From the coordinates we can tell the lengths of the sides, and the triangle shows that <em>u</em> is the hypotenuse of the triangle. This triangle is also a right triangle, so u can use Pythagoras' theorem to find the length of <em>u</em>.

a^{2}+b^{2} = c^{2} \\6^{2}+4^{2}  = c^{2} \\\sqrt{6^{2} +4^{2} } = c\\\sqrt{36+16} = c\\7.21 = c

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Hope this helps!

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The formula for the area of the triangle is:

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Step-by-step explanation:

We are given a right triangle with a height of 8<em>x</em> and a base of 6<em>x</em>.

The area of a triangle is given by the formula:

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The hypotenuse will be:

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