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liraira [26]
4 years ago
14

Which statement about histograms is true?

Mathematics
2 answers:
zhannawk [14.2K]4 years ago
6 0

Answer:

The third one is correct, the others bend the truth as they can touch but not overlap. As the third one states 'They are organized in equal intervals.'  this means they share an equal growth opportunity within their own column, their own height and nominated place within the histogram. The bars are of equal width and correspond to the equal class intervals. But on rare occasions like size classes they can be shown as a wider variant within their groups. Example would be showing a wider column say on classes at a school as the width and data being achieved forces a true event of variant sizes in education upon the base of the graph, this rarely applies to staff graphs as planning for schools is a wider data share than say offices using these types of graphs. Work development would use just data percentages along with the frequencies is one example so group size are stated in the reports to support more specific data in the graphs instead.

Step-by-step explanation:

To display numerical data that has been organized into equal intervals. The bars should touch the adjacent bars but not overlap. These intervals allow you to see the frequency distribution of the data, or how many pieces of data are in each interval.

melisa1 [442]4 years ago
3 0
c :)
explanation
c :)
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Step-by-step explanation:

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7 0
3 years ago
Slope of line that passes through points (2,1) and (17,-17)
mojhsa [17]

Answer: y = -1,2x + 3.4

Step-by-step explanation:

y = ax + b

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7 0
3 years ago
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2 years ago
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quester [9]

To find Angle A we use cosine

cos ∅ = adjacent / hypotenuse

From the question

The adjacent is 17

The hypotenuse is 38

So we have

cos A = 17/38

A = cos-¹ 17/38

A = 63.4

<h3>A = 63° to the nearest degree</h3>

To find Angle C we use sine

sin ∅ = opposite / hypotenuse

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7 0
3 years ago
how does the appearence of a histogram change when u use many small intervals then when you use a few large intervals
vampirchik [111]
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5 0
3 years ago
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