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olganol [36]
3 years ago
12

Graph y= 1/2x–3 . Where would I put the points ?

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
5 0
Multiply the multiply the number by the fraction
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there is an unknown number in the sequence counting backward. The number is after 48. The number is before 46. What is the unkno
Ghella [55]
The unknown number is 47.
5 0
3 years ago
Ricardo lost 6 golf balls while playing yesterday he bought a box of twelve golf balls and lost 4 on the course today he now has
umka2103 [35]
16 balls. 

Let's call x the total number of golf balls that Ricardo had before he lost the first 6 balls. (x - 6).
Then he bought 12 more and lost 4 so basically 12 - 4 = 8
Add that to the equation: (x-6) + 8
And now that he has 18 golf balls at end of the second day the total must add to 18.

Full equation: (x-6) + 8 = 18

(x-6) + 8 = 18
(x-6) = 18 - 8 <-- Transpose
(x-6) = 10
16 - 6 = 10 <-- What would x have to be inoder to make this equation true? 16!
So x = 16

16 is the number of golf balls the Ricardo began with.

8 0
3 years ago
Proportions and Similarity
nekit [7.7K]

\bf \cfrac{length}{width}\qquad \qquad \stackrel{A}{\cfrac{4}{5}}\qquad \stackrel{B}{\cfrac{20}{25}}\implies \cfrac{4}{5}\qquad \checkmark

5 0
3 years ago
In the figure, Δ ABC Δ XYZ. What is the perimeter of ΔABC? Show your work.
slava [35]

Answer:

49

Step-by-step explanation:

∆ABC~ ∆XYZ

AB= 11 that is half of XY = 22

therefore XZ/2 = AC (base) = 32/2 = 16

and YZ /2 = BC(hypotenuse) = 44/2 = 22

(a= 11, b= 16, c= 22)

perimeter of a triangle

P = a+b+c

P= 11+16+22= 49

8 0
3 years ago
) Asuka travels at an average speed of 50 mph for 20 miles.
Anuta_ua [19.1K]

Answer: 41.86 miles/hour

Step-by-step explanation:

Use Distance = Speed*Time to find the two missing values with the data that is provided for those two cases [<em>in brackets</em>].

MPH MILES     HOURS

 50            20      [<em>0.4]</em>

 [<em>40</em>]    <u>70</u>      <u>1.75</u>

Totals   90 miles   2.15 hours

Average = 90 miles/2.15 hours

     41.86 mph

5 0
3 years ago
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