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2 years ago

Simplify the expression. show each step. -5 x 1 x 11 x 4

Mathematics

2 answers:

Luba_88 [7]2 years ago

3 0

Step 1:

0 - ((5x • x11) • x4)

Final result :

-5x16

lorasvet [3.4K]2 years ago

3 0

Answer:

−5x^16

Step-by-step explanation:

(−5)*x1*x11*x4

=−5*x16

=−5x^16

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1/3 divided by 2 divided

KatRina [158]

Answer:

1/6

Step-by-step explanation:

1/3 diveded by 2/1

1/3x1/2 = 1/6

Hope it helps:)

6 0

1 year ago

Assume all variables represent non negative numbers . Help please!!

Dafna1 [17]

Answer:

A). $2p^{8}$

B). $3m^{7}$

Step-by-step explanation:

A). $\sqrt{4p^{16}}$

To get the square root of the given expression we will convert it into the square form.

$4p^{16}=(2)^2(p^{8})^2$ [Since 2×2 = 4 and $p^{8}\times p^{8}=p^{16}$ ]

Therefore, $\sqrt{4p^{16}}=\sqrt{2^{2}\times (p^{8})^2 }$

$=2p^{8}$

B). $\sqrt{9m^{44}}$

Since, $9m^{14}=(3)^2\times (m^7)^2$

Therefore, $\sqrt{9m^{44}}=\sqrt{(3)^2\times (m^7)^2}$ [Since 3² = 9 and (m⁷)² = m¹⁴]

$=3m^{7}$

7 0

2 years ago

What is A if a is equal to 1

MA_775_DIABLO [31]

A would be equal to 1 since a is equal to one already

3 0

1 year ago

Read 2 more answers

2. If AB = 4x + 9. BC = 5x + 2, and AC = 56, then find the value for . AB, BC.<br> A<br> B

inysia [295]

Answer:

AB=29; BC=27

Step-by-step explanation:

So they told us AB=4x+9 and that BC=5x+2, and AC=56 , now to help with the question you can draw this information on a number line. Now on a number you can see that basically AC=AB+BC.

So you would write it as such,,

4x+9+5x+2=56

Combine like terms

9x+11=56

Now you have to isolate the x by itself but first get rid of the 11.

9x+11-11=56-11

You would get

9x=45

Here you can divide 9 by both sides to isolate x.

9x/9=45/9

{x=5}

Now to find the value for both substitue x in the equations for both

1. AB=4x+9 where x is 5

4(5)+9 =AB

20+9 =AB

29=AB

You would do the same with BC

2. BC= 5x+2 where x is 5

5(5)+2= BC

25+2= BC

27=BC

If you want to check your answers you can just substitute x for 5 in the first equation we did where AC=AB+BC

6 0

2 years ago

Verify the following trig identities.

bagirrra123 [75]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• 1 + cot² x = csc²x and csc x = $\frac{1}{sinx}$

• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Consider the left side

sin²Θ( 1 + cot²Θ )

= sin²Θ × csc²Θ

= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified

-----------------------------------------------------------------

Consider the left side

cos²Θ - sin²Θ

= cos²Θ - (1 - cos²Θ)

= cos²Θ - 1 + cos²Θ

= 2cos²Θ - 1 = right side ⇒ verified

3 0

2 years ago