Which expression is equivalent to sqrt -108 - sqrt -3

Mathematics

2 answers:

Artyom0805 [142]2 years ago

5 0

sqrt (-108) - sqrt (-3)

sqrt(-1) sqrt(108) - sqrt(-1) sqrt(3)

sqrt(-1)*sqrt(36)*sqrt(3)-sqrt(-1)sqrt(3)

sqrt(-1)sqrt(3) (6-1)

isqrt(3)5

5isqrt(3)

Choice A

xxTIMURxx [149]2 years ago

4 0

answer : Option A

$\sqrt{-108} - \sqrt{-3}$

first we simplify each square root

The value of square root (-1) = i, to remove negative inside the square root we use 'i'

$\sqrt{-108} =\sqrt{-36* 3}= 6i\sqrt{3}$

$\sqrt{-3} = i\sqrt{3}$ (we cannot simplify square root (3))

$\sqrt{-108} - \sqrt{-3}$

$6i\sqrt{3} - i\sqrt{3}$

Both are like terms, so we subtract it

$5i\sqrt{3}$

$5\sqrt{3} i$

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valentina_108 [34]

Answer:

Step-by-step explanation:

Consider curl $(fF)$ where $f$ is a scalar function and F is a vector function

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i j k

$curl(fF) = \frac{\partial}{\partial x}$ $\frac{\partial}{\partial y}$ $\frac{\partial}{\partial z}$

$fF_{1}$ $fF_{2}$ $fF_{3}$

$curl(fF)=i(\frac{\partial}{\partial y}(fF_{3})-\frac{\partial}{\partial z}(fF_{2}))-j(\frac{\partial}{\partial x}(fF_{3})-\frac{\partial}{\partial z}(fF_{1}))+k(\frac{\partial}{\partial x}(fF_{2})-\frac{\partial}{\partial y}(fF_{1}))$

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