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maria [59]
3 years ago
14

Which expression is equivalent to 3 sqrt (x^5y)

Mathematics
1 answer:
Marat540 [252]3 years ago
7 0

Answer:

3x^{2}\sqrt{xy}

Step-by-step explanation:

we have

3\sqrt{x^{5}y}

we know that

\sqrt{x^{5}} =\sqrt{x*x^{4}}=x^{2}\sqrt{x}

substitute

3\sqrt{x^{5}y}=3x^{2}\sqrt{xy}

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Margo's parents started a savings account when she started highschool. They put in $12,500 to start. If the account earns 7% sim
eduard

Answer:

probably bout like 4 dollars

Step-by-step explanation:

7 0
2 years ago
Fredericka can make 65 percent of her shots from the free throw line if she shoots 75 times how many shoots can she expect to ma
Mademuasel [1]

Answer:

48.75 shots are made (just round according to the instructions your teacher gave you)

Step-by-step explanation:

In the attached picture I provided two different ways to solving the problem, but if these do not click with you, I am sure you can find other ways of solving that work better for you :)

5 0
4 years ago
A rat is trapped in a maze. Initially he has to choose one of two directions. If he goes to the right, then he will wander aroun
Brut [27]

Answer:

The expected number of minutes the rat will be trapped in the maze is 21 minutes.

Step-by-step explanation:

The rat has two directions to leave the maze.

The probability of selecting any of the two directions is, \frac{1}{2}.

If the rat selects the right direction, the rat will return to the starting point after 3 minutes.

If the rat selects the left direction then the rat will leave the maze with probability \frac{1}{3} after 2 minutes. And with probability \frac{2}{3} the rat will return to the starting point after 5 minutes of wandering.

Let <em>X</em> = number of minutes the rat will be trapped in the maze.

Compute the expected value of <em>X</em> as follows:

E(X)=[(3+E(X)\times\frac{1}{2} ]+[2\times\frac{1}{6} ]+[(5+E(X)\times\frac{2}{6} ]\\E(X)=\frac{3}{2} +\frac{E(X)}{2}+\frac{1}{3}+\frac{5}{3} +\frac{E(X)}{3} \\E(X)-\frac{E(X)}{2}-\frac{E(X)}{3}=\frac{3}{2} +\frac{1}{3}+\frac{5}{3} \\\frac{6E(X)-3E(X)-2E(X)}{6}=\frac{9+2+10}{6}\\\frac{E(X)}{6}=\frac{21}{6}\\E(X)=21

Thus, the expected number of minutes the rat will be trapped in the maze is 21 minutes.

3 0
4 years ago
Marks age next year will be three times jims age from 2 years ago. If the sum of their ages now is 21, how old are they? plz hel
miv72 [106K]

Answer: Mark is 14 and Jim is 7.

Step-by-step explanation: It says that next year Mark will be threee times older than Jim was 2 years ago.

The wrk is:

7-2=5(Jims age 2 years ago)

5x3=15

15-1=14(you subtract 1 because Mark's current age is 14 because it says that next year it will be 3 times Jim's)

8 0
4 years ago
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