All categories

3 years ago

In which quadrant is the number 6 – 8i located on the complex plane?

Mathematics

2 answers:

alexandr402 [8]3 years ago

5 0

Answer: The given number is located in Quadrant IV.

Step-by-step explanation: We are to find the quadrant in which the number (6 - 8i) located on the complex plane.

We know that a complex plane is treated as a two-dimensional plane, where the real part of the number is treated as the x-coordinate and the imaginary part is treated as the y-coordinate.

So, if 'x' and 'y' are positive, then

x + yi = (x, y) Quadrant I

-x + yi = (-x, y) Quadrant II

-x - yi = (-x, -y) Quadrant III

x - yi = (x, -y) Quadrant IV

Given number is

(6 - 8i) = (6, -8).

Therefore, the given number is located in Quadrant IV.

zavuch27 [327]3 years ago

3 0

The answer is the 4th quadrant xx <span>The real axis is the x-axis and the imaginary axis is the y-axis</span>

You might be interested in

How do you write 11/20 as a percentage

rewona [7]

Answer:

55%

Step-by-step explanation:

11/20 =

11 ÷ 20 =

0.55 =

0.55 × 100/100 =

0.55 × 100% =

8 0

2 years ago

Read 2 more answers

What is the shaded portion of the circle

blagie [28]

Answer:

$(5\pi-11.6)\ ft^{2}$

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector minus the area of the triangle

step 1

Find the area of the circle

the area of the circle is equal to

$A=\pi r^{2}$

we have

$r=5\ ft$

substitute

$A=\pi (5)^{2}$

$A=25\pi\ ft^{2}$

step 2

Find the area of the sector

we know that

The area of the circle subtends a central angle of 360 degrees

by proportion find out the area of a sector by a central angle of 72 degrees

$\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}$

step 3

Find the area of triangle

The area of the triangle is equal to

$A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}$

step 4

Find the area of the shaded region

Subtract the area of the triangle from the area of the sector

$(5\pi-11.6)\ ft^{2}$

8 0

2 years ago

Explain the advantages and disadvantages of each payment method.

kakasveta [241]

$ 110 he had 185 in his account then he needs to take away 75 from his account

6 0

3 years ago

How far did this person travel in Section C ( hours 6-7) Remember to include units

cestrela7 [59]

From C in 1 hour they traveled 30 miles

5 0

2 years ago

Quadratic equations and complex numbers PLEASE HELPPPP ASAP

kondor19780726 [428]

we are given

$27x^3-1=0$

we can also write it as

$(3x)^3-(1)^3=0$

now, we can use factor formula

$a^3-b^3=(a-b)(a^2+ab+b^2)$

we can use above formula

we get

$(3x)^3-(1)^3=(3x-1)((3x)^2+3x\times 1+(1)^2)$

now, we can simplify it

$27x^3-1=(3x-1)(9x^2+3x+1)$

now, we can set it to 0

$27x^3-1=(3x-1)(9x^2+3x+1)=0$

and then we can solve for x

$(3x-1)(9x^2+3x+1)=0$

$3x-1=0$

$x=\frac{1}{3}$

$9x^2+3x+1=0$

now, we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can plug values

and we get

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:9\cdot \:1}}{2\cdot \:9}$

$x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$

So, we will get solution as

$x=\frac{1}{3},\:x=-\frac{1}{6}+i\frac{\sqrt{3}}{6},\:x=-\frac{1}{6}-i\frac{\sqrt{3}}{6}$ ...............Answer

5 0

3 years ago