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kari74 [83]
3 years ago
6

, write two equivalent fractions for each given fraction.4/10= ​

Mathematics
1 answer:
Goshia [24]3 years ago
4 0

Answer: 4/10 = 2/5 and 8/20

Step-by-step explanation: Simply divide 4/10 by 2 to get 2/5 and then multiply by 2 to get 8/20. Hope this helped!

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A 2-kilogram bag of flour costs $4.70. What is the unit price?
Aleonysh [2.5K]

Answer:

$2.35

Step-by-step explanation:

4.70/2= 2.35

8 0
3 years ago
HELP ASAP Which expression is equivalent to this polynomial expression?
Evgesh-ka [11]

Answer:

B, if you have any questions how I did anything, or questions in general, let me know.  

Step-by-step explanation:

First you want to make sure you understand distributing.  Just using variables I will show how to districute a similar expression.

(a - b)(c + d - e)

There are several ways to think of it.  you could treat (a-b) as one term and distribute it into c + d - e like this.  pretend (a- b) = x

x(c + d - e) = cx + dx - ex = c(a-b) + d(a-b) - e(a-b)

Then just do a bit more distributing, then combine like terms.

You could instead make (c + d - e) a single term and distribute that into (a-b)

I prefer doing it all in one step, similar to FOIL-ing.  Take the first term of one of the expression in parenthesis and distribute it, then move on to the second and so on.

so with (a - b)(c + d - e) I would start with a and distribute that into (c + d - e) and get ac + ad - ae then do the same to -b and get -bc - bd + be then you add the two parts together. ac + ad - ae + -bc - bd + be = ac + ad - ae -bc - bd + be.  Then you would combine like terms.  Let me know if you need help with that.  

Anyway, now for your problem.  Keep in mind you can use any of the methods.

(2x^2 - 3y^2)(4x^4 + 6x^2y^2 + 9y^4)

First distribute 2x^2 into (4x^4 + 6x^2y^2 + 9y^4)

8x^6 + 12x^4y^2 + 18x^2y^4

Next distribute -3y^2 into (4x^4 + 6x^2y^2 + 9y^4)

-12x^4y^2 - 18x^2y^4 - 27y^6

Now add the two together.

8x^6 + 12x^4y^2 + 18x^2y^4 + -12x^4y^2 - 18x^2y^4 - 27y^6 = 8x^6 + 12x^4y^2 + 18x^2y^4 - 12x^4y^2 - 18x^2y^4 - 27y^6

Finally combine like terms.

12x^4y^2 - 12x^4y^2 = 0

18x^2y^4 - 18x^2y^4 = 0

So that leaves us with 8x^6 - 27y^6

B is the only answer that works, none of the other 3 can be simplified or adjusted to make them equal what we need, so B is the only right answer.  

If you have any questions though let me know.

5 0
3 years ago
Which of the following equations have the same solution? Give reasons for your answer that do not depend on solving the equation
topjm [15]

<u>Answer:</u>

A,C and E are equal with 4 as their solution; F and B are equal with 0 as their solution. D is independent.

<u>Solution:</u>

A. -(7-4x)=9

Taking off the brackets we get,

-7+4x=9 \Rightarrow +4x=9+7

\Rightarrow 4x=16 \\

\Rightarrow x=\frac{16}{4} \Rightarrow 4

Here x=4 --- (a)

B. 12=-4(-6x-3)

Multiplying -4 inside we get,

12=+24x+12 \Rightarrow 12-12=24x

\Rightarrow x=0

Here x=0 --- (b)

C. 5x+34=-2(1-7x)

Multiplying -2 inside we get,

5x+34=-2+14x

Grouping the terms,

34+2=14x-5x \Rightarrow 36=9x

\Rightarrow x=4

Here x=4 --- (c)

D. 14=-(x-8)

\Rightarrow 14=-x+8 \Rightarrow -x=14-8

\Rightarrow x=-6

Here x=-6 --- (d)

E. -8=-(x+4)

\Rightarrow -8=-x-4 \Rightarrow x=8-4

\Rightarrow x=4

Here x=4 --- (e)

F. x+5=-5x+5

\Rightarrow x+5x=5-5

6x=0 \Rightarrow x=0

Here x=0 --- (f)

So, from the above calculations we can conclude that (a), (c) and (e) are equal and (f) and (b) are equal but (d) is independent because it has a different solution.

5 0
3 years ago
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