The answer is (f o g)(x) = 2x^2 - 13
In order to find a composite function, you take the first letter (in this case f) and use that equation. You then remove the variable and put in the second letter (g).
f(x) = 2x + 1 ----> Remove variable.
f(x) = 2( ) + 1 ----> Insert g(x)
(f o g)(x) = 2(x^2 - 7) + 1 ----> Distribute
(f o g)(x) = 2x^2 - 14 + 1 ----> Simplify
(f o g)(x) = 2x^2 - 13
If two tangent segments to a circle share a
common endpoint outside a circle, then the two segments are congruent. This
is according to the intersection of two tangent theorem. The theorem states
that given a circle, if X is any point
within outside the circle and if Y and Z are points such that XY and XZ are
tangents to the circle, then XY is equal to XZ.
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This is the graph of the equation
Answer:
Its a rhombus
Step-by-step explanation:
Answer:
The best way to know weather the formula y=x⁴-4x³+3x² is growing or not, is by graphing it.
As you can see in the attached picture:
- For -inf<x< 0 the graph decreases.
- For 0<x<0.634 the graph is growing
- For 0,634<x<2.366 the graph decreases
- For 2.366<x<+inf the graph is growing.
Therefore, the polynomial grows in the intervals stated before.
