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pav-90 [236]
3 years ago
15

Solve for the measure of each angle indicated. please help we never learned this in class.

Mathematics
1 answer:
bija089 [108]3 years ago
7 0

Answer:

Step-by-step explanation:

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Mrac [35]
You add 13 and 8 it gets 21 so for X its 13
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4 years ago
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The point (6, - 5) is reflected across the y axis what is the new point
jonny [76]

Answer:

  (-6, -5)

Step-by-step explanation:

Reflection across the y-axis leaves the point on the same horizontal line, but with the sign of its x-coordinate changed.

  (x, y) ⇒ (-x, y) . . . . . reflection across the y-axis

  (6, -5) ⇒ (-6, -5)

The image point is (-6, -5).

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2 years ago
BRAINLIEST TO BEST IN DEPTH ANSWER (NO BRAINLY IF DOESN'T ANSWER ALL QUESTIONS
elena55 [62]
Answer for question 1: B. Because 10 times 1 is 10 kg and is not close to 100

Answer for question 2: B. because it is within the scientific measurement of between 1-10

Answer for question 3: C. Because 24-2 is 22

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3 years ago
What is the distance between parallel lines whose equations are y = 2x + 7 and y = 2x – 3?
malfutka [58]

Answer:

The distance is \sqrt{20} or 2\sqrt{5}.

Step-by-step explanation:

Slope of parallel: 2

Slope of perpendicular: -1/2

Pick a point for y =2x + 7. For example (0,7)

Use the perpendicular slope to get to the other line to find the other point of y=2x-3. Look at the screenshot...I got (4,5).

Distance formula \sqrt{(x_{2}-x_{1} )^{2}+(y_{2} -y_{1})^2   }

Insert (0,7) and (4,5)

\sqrt{(0-4)^{2}+(7-5)^2   } = \sqrt{(-4)^{2}+(2)^2   } = \sqrt{(16)+(4)}  } = \sqrt{20}  = 2\sqrt{5}

6 0
2 years ago
The image of the polygon ABCDE reflected across the x-axis. A(-1,-1),B(0,1),C(4,2),D(6,0),E(3,-3) The vertices of the image are.
4vir4ik [10]

A reflection across the x-axis has the rule:

(x,y)→(x,-y).

Then:

  • A(-1,-1)→A'(-1,1),
  • B(0,1)→B'(0,-1),
  • C(4,2)→C'(4,-2),
  • D(6,0)→D'(6,0),
  • E(3,-3)→E'(3,3).

Answer: the vertices of the image are A'(-1,1), B'(0,-1), C'(4,-2), D'(6,0) and E'(3,3).

6 0
4 years ago
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