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BabaBlast [244]
3 years ago
7

Factor. 3ab-6b^2-2bc+ac (Thank you, please explain all steps)

Mathematics
2 answers:
Norma-Jean [14]3 years ago
8 0

Answer:

(a-2b)(3b-c)

Step-by-step explanation:

3ab-6b^2-2bc+ac

Let's rearrange

3ab+ac-6b^2-2bc

Let's factorise

a(3b+c)-2b(3b+c)

(a-2b)(3b+c)

Since the answer cannot be solved further

The answer is (a-2b)(3b+c)

Vinvika [58]3 years ago
6 0

Answer:

(3b + c)(a - 2b)

Step-by-step explanation:

Given

3ab - 6b² - 2bc + ac ← Rearranging

= 3ab + ac - 6b² - 2bc (factor the first/second and third/fourth terms )

= a(3b + c) - 2b(3b + c) ← factor out (3b + c) from each term

= (3b + c)(a - 2b)

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