Answer:
1.875
Step-by-step explanation:
It should be 2 but i’m not positive
Answer: A, 1/2
Step-by-step explanation:
he is simply using 1 cup of bs for each cup of ws so when you do it its i cup of ws then its hald of 1 bs
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
Answer:
-15
Step-by-step explanation:
start from the inside and go out.
So first plug in -3 into g(x)
g(-3) = -3 - 7 = -10
then plug in -10 into f(x)
f(-10) = 2(-10) + 5 = -15
so f(g(x)) = -15
