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mylen [45]
3 years ago
6

The boiling point of jet fuel is 329°

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Since, the boiling point of jet fuel  = 329 °F

We have to convert the boiling point of jet fuel in ^\circ C.

The expression which is used to convert ^\circ F to ^\circ C is given by:

C = \frac{5}{9}(F-32)

= \frac{5}{9}(329-32)

= \frac{5}{9}(297)

= 165^\circ C

Therefore, the boiling point of jet fuel is 165 ^\circ C.

Tatiana [17]3 years ago
7 0

Answer:

Since, the boiling point of jet fuel  = 329 °F

We have to convert the boiling point of jet fuel in .

The expression which is used to convert  to  is given by:

C =

=

=

= 165

Step-by-step explanation:

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3 years ago
Simplify the expression using long division. (10x2 – 85x – 10) ÷ (x – 8)
Lelechka [254]

Answer: 5 • (2x2 - 17x - 2)

 ———————————————————

        x - 8      

Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 

Step  2  :

           10x2 - 85x - 10

Simplify   ———————————————

                x - 8      

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  10x2 - 85x - 10  =   5 • (2x2 - 17x - 2)  

Trying to factor by splitting the middle term

3.2     Factoring  2x2 - 17x - 2  

The first term is,  2x2  its coefficient is  2 .

The middle term is,  -17x  its coefficient is  -17 .

The last term, "the constant", is  -2  

Step-1 : Multiply the coefficient of the first term by the constant   2 • -2 = -4  

Step-2 : Find two factors of  -4  whose sum equals the coefficient of the middle term, which is   -17 .

     -4    +    1    =    -3  

     -2    +    2    =    0  

     -1    +    4    =    3  

Observation : No two such factors can be found !!  

Conclusion : Trinomial can not be factored

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Step-by-step explanation:

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