Answer:
the distance from point C to D is 7.75m
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one. Please have a look at the attached photo
<em>A vertical flagpole, AB,has a height of 46m. The points B, C and D lie on level ground, and BCD is a straight line Point C is 21 m from the base of the flagpole. The angle of elevation of the top of the flagpole from point D is 58 degrees</em>
<em>How far apart are points C and D? </em>
My answer:
Given the infomation:
- AB: 46m
- BCD is a straight line
- BC = 21m
In triangle ABD, with angle of elevation from D to top of flag pole is 58 degrees.
<=>
<=> tan(58) = ![\frac{AB}{BD}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7BBD%7D)
<=> BD =
<=> BD = ![\frac{46}{1.6}](https://tex.z-dn.net/?f=%5Cfrac%7B46%7D%7B1.6%7D)
<=> BD = 28.75
From the figure:
BD = BC + CD
<=> CD = BD - BC
<=> CD = 28.75 - 21 = 7.75m
So the distance from point C to D is 7.75m