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2 years ago

15

If the population mean payment time is 19.5 days, what is the probability of observing a sample mean payment time of 65 invoices

less than or equal to 18.1077 days?

1 answer:

Maksim231197 [3]2 years ago

5 0

Answer: P(mean x<18.1077) = P(z< -2.67) = 0.0038

Step-by-step explanation:

Value of Z for 18.1077 = (18.1077 - 19.5)/0.5209 = -2.67

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Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

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3 years ago

12 + 4x > 24 or 10 - 12x > 22

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2 years ago

If the circumference is 34.54 units what is the radius

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3 years ago

F(x)=12x2-4x-8. G(x)=11x-6

AlekseyPX

Answer: Second option.

Step-by-step explanation:

Given the functions f(x) and g(x):

$f(x)=12x^2-4x-8\\\\g(x)=11x-6$

You need to divide them in order to find $(\frac{f}{g})(x)$ asked in the exercise. Then:

$(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}$

Now, it is important to remember that, by definition, the division by zero is not defined. Therefore, the denominator of the function cannot be zero.

Let's find the value of "x" for which the denominator of the function would be zero:

1. You need to make the denominator equal to zero:

$11x-6=0$

2. Finally, you must solve for "x":

$11x=6\\\\x=\frac{6}{11}$

Therefore, as you can see, the answer is:

$(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}$ , $x=\frac{6}{11}$

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