Question

A concert hall is in the shape of a rectangle. Its floor has a length of (x + 6) meters and a width of (2x - 3) meters. Write a simplified expression that represents the area of the floor of the concert hall, in square meters?

Answer 1

Answer:

$A=(2x^{2}+9x-18)\ m^{2}$

Step-by-step explanation:

Let

L-----> the length of the concert hall

W----> the width of the concert hall

we know that

The area of a rectangle ( concert hall) is equal to

$A=LW$

we have

$L=(x+6)\ m$

$W=(2x-3)\ m$

substitute the values

$A=(x+6)(2x-3)\\ \\A=2x^{2} -3x+12x-18\\ \\A=(2x^{2}+9x-18)\ m^{2}$