Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg
1 answer:
Answer:
The potential energy associated with the given mass equals 1814.98 kilo Joules.
Step-by-step explanation:
We know that for a object of mass 'm' standing at a height of 'h' meters above the surface of earth the potential energy associated with the object is given by
where
'g' is acceleration due to gravity.
Since it is given that mass of 1 cubic meter of water is 1000 kilograms that the mass associated with given quantity of water is also 1000 kilograms since the volume is 1 cubic meter.
The height is given as 607 feet = meters
Applying the values in the above equation we get
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and you can combine the logarithms if you like as