<span>y = 10x * sin(x)
y' = 10 * (x * cos(x) + sin(x))
x = pi/2
y' = 10 * ((pi/2) * cos(pi/2) + sin(pi/2)) = 10 * ((pi/2) * 0 + 1) = 10 * 1 = 10
y - 5pi = 10 * (x - (pi/2))
y - 5pi = 10x - 5pi
y = 10x</span>
Pythagorean theorem you times 40 by 2 then 9 by 2 then square root
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
Exponential would be the correct answer I believe...
The decimal conversion to 8 39/40 is 8.975 and the decimal terminates.
