Answer:
A sample size of 664 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
99% confidence level
So , z is the value of Z that has a pvalue of , so .
If the candidate only wants a 5% margin of error at a 99% confidence level, what size of sample is needed
A sample size of n is needed.
n is found when M = 0.05.
We have no estimate, so we use . Then
Rounding up
A sample size of 664 is needed.