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olasank [31]
3 years ago
9

Flying with the wind a plane went 198 mph. Flying into the same wind the plane only went 162 mph. Find the speed of the plane in

still air and the speed of the wind
Mathematics
1 answer:
olganol [36]3 years ago
4 0

Answer: speed of plane in still air is 180 miles per hour

speed of the wind is 18 miles per hour

Step-by-step explanation:

Flying with the wind, the plane went 198 miles per hour. This means if was flying in the same direction with the wind. This is same as the speed in still air because there was no opposition from the wind.

Flying into the same wind the plane only went 162 mph. This means that the plane flew against the wind

Let x = the speed of the plane

Let y = the speed of the wind

when flying with the wind,

x + y = 198 - - - - - - -1

When flying against the wind,

x - y = 162 - - - - - - - -2

Subtracting equation 2 from equation 1,

y - - y = 198 - 162

2y = 36

y = 36/2 = 18 miles per hour

x = 198 - y = 198 -18

x = 180 miles per hour

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Can someone pls help me
erica [24]

I would love to help you :)

So what do we know?:

We know that side A has a length of 25, and side B has a length of 21.

So that leaves us to find the length of side C correct?

Answer

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4

(most likely incorrect LOL)

<u><em>IM SO SORRY IF I MADE YOU FAIL THE QUESTION SDNFKJSDFSDF</em></u>

5 0
2 years ago
Read 2 more answers
What is the solution to the following equation?
Liono4ka [1.6K]

Answer: X-3(2x-8)= -25

A. X= 11

B. X= 14

C. X=10

D. x=5

Step-by-step explanation:

4 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
What is the solution to this equation?
kupik [55]

Answer:

x = 5

Step-by-step explanation:

3x - 7 + 4x = 28

Combine like terms

7x -7 = 28

Add 7 to each side

7x - 7 +7  = 28+7

7x = 35

Divide each side by 7

7x/7 = 35/7

x = 5

4 0
3 years ago
Read 2 more answers
Please help!!!!!!!​
Serhud [2]

Answer:

152

Step-by-step explanation:

12+16=28 so 180 is the total and 180-28=<u>152</u>

<u />

3 0
3 years ago
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