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BARSIC [14]
3 years ago
13

What is the solution to negative start root 75 end root to the nearest integer?

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0
The two square numbers that are nearest to 75 are 64 and 81. The square root of 64 is 8 while the square root of 81 is 9. Thus, the square root of 75 should fall between these two integers. 

The square root of 75 is equal to 8.66 which is nearest to 9. Hence, the answer is 9. 
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7 0
3 years ago
1st question: Reuben received 80 dollars. Write a signed number to represent this change.
lesya692 [45]

Answer:

1) +80

2) -1520

Step-by-step explanation:

Positive Signed numbers are used in real world situations to indicate the increase. Examples include; increase in weight, deposit of money into an account, increase in income, profit, height above sea level, etc. They are all represented by positive signed numbers.

Whereas, negative signed numbers show decrease. Examples include; loss of weight, withdrawal of money from an account, loans, liabilities, losses, temperature below zero degrees, height below sea level.

1) We are told that Reuben received 80 dollars. Thus, it means he received an increase in the amount of money he already had. Thus, the signed number will be +80.

2) We are told that A car corporation produced 1520 fewer cars this month than last.

Thus, the signed number will be negative since there is a decrease in number of cars.

Thus, signed number = -1520

7 0
2 years ago
Prove the following statement.
jolli1 [7]
<h2>Step-by-step explanation:</h2>

As per the question,

Let a be any positive integer and b = 4.

According to Euclid division lemma , a = 4q + r

where 0 ≤ r < b.

Thus,

r = 0, 1, 2, 3

Since, a is an odd integer, and

The only valid value of r = 1 and 3

So a = 4q + 1 or 4q + 3

<u>Case 1 :-</u> When a = 4q + 1

On squaring both sides, we get

a² = (4q + 1)²

   = 16q² + 8q + 1

   = 8(2q² + q) + 1

   = 8m + 1 , where m = 2q² + q

<u>Case 2 :-</u> when a = 4q + 3

On squaring both sides, we get

a² = (4q + 3)²

   = 16q² + 24q + 9

   = 8 (2q² + 3q + 1) + 1

   = 8m +1, where m = 2q² + 3q +1

Now,

<u>We can see that at every odd values of r, square of a is in the form of 8m +1.</u>

Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.

Hence , it is clear that square of an odd positive is in form of 8m +1

3 0
3 years ago
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