Answer:

Step-by-step explanation:
Convert the mixed number to the fraction:

METHOD 1:

METHOD 2:

When Fiona rolled Cube #2, she got a number -2 as she got 2 while rolling Cube #1 and the sum of the value on the cubes was 0.
As we know Cube #1 has integers 1, 2, 3, 4, 5, 6 on its faces and Cube #2 has -1, -2, -3, -4, -5, -6 on its faces.
It is also given that Fiona got 2 when she rolled cube #1 and the value of the sum on both the cubes is 0.
So it is clear that on Cube #2, the number must be -2 as in that case only, the sum of the values will be 0.
To prove
2 + (-1) = 1
2 + (-2) = 0
2 + (-3) = -1
Hence, the number she got on Cube #2 is -2.
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Answer:
9/35
all the boxes in one row are 7 and the number of rows are 5 .. so 7x5=35 and the number of boxes shaded are 9
To know what to do first in a math problem we look to order of operations... PEMDAS stands for parentheses, exponents, multiplication, division, addition, and subtraction. So to begin we look for parentheses... do we have any? Why, yes, yes we do. Let's work!
(3+3) + 6 / 3 + 6 =
Add 3+3 in the parentheses. Since there is nothing else, the parentheses can go away.
6 + 6 / 3 + 6 =
Now, any exponents? Nope... Multiplication? Nope... division? Yes! Let's go!
6 + 2 + 6 =
Now all we have left is addition... Go for it!
8 + 6 = 14
Done!
The volume of the region R bounded by the x-axis is: 
<h3>What is the volume of the solid (R) on the X-axis?</h3>
If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.
From the given graph:
The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

here:
- (x₁, y₁) and (x₂, y₂) are two points on the straight line
Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8) from the graph, we have:

y = 4x
Now, our region bounded by the three lines are:
Similarly, the change in polar coordinates is:
where;
- x² + y² = r² and dA = rdrdθ
Therefore;
- rsinθ = 0 i.e. r = 0 or θ = 0
- rcosθ = 2 i.e. r = 2/cosθ
- rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)
- ⇒ r = 0 to r = 2/cosθ
- θ = 0 to θ = tan⁻¹ (4)
Then:


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