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cestrela7 [59]
3 years ago
10

Which change will double the lateral surface area of a regular triangular pyramid with base length b , height h , and slant heig

ht l ?
Mathematics
1 answer:
Veronika [31]3 years ago
3 0
A regular triangular pyramid is a solid figure with r surfaces

- 3 lateral surfaces and one base surface

- the four surfaces are congruent triangles, which is to say that all triangular surfaces have the same base and the same slant heght

- the area of each surface is [1/2] base * slant height.

Then, a change that double the area is any that keep one of the dimensiones and double the other.

So the answer is:  double each side, b, of the base triangle while keeping the slant height, l, tha same.


You can also double the slant height, l, while keeping the base triangle, but then the height,h, of the pyramid will increase, by a factor which is not 2.
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Using scientific notation, it is found that:

67 ns = 6.7 \times 10^{-8}s

<h3>What is scientific notation?</h3>

A number in scientific notation is given by:

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With the base being a \in [1, 10).

In this problem, the amount is of 67 ns.

Each ns has 10^{-9} seconds, hence:

67ns = 67 \times 10^{-9}s

We want the base between 1 and 10(exclusive), hence, we move the decimal digit one digit to the left and add one to the exponent, and the representation is:

67 ns = 6.7 \times 10^{-8}s

You can learn more about scientific notation at brainly.com/question/16394306

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