Answer:
![\[x^{\frac{1}{4}}\]](https://tex.z-dn.net/?f=%5C%5Bx%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5D)
Step-by-step explanation:
x is a variable which has been declared of type double.
Then square root of x can be expressed as ![\[\sqrt{x}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7Bx%7D%5C%5D)
The quartic root of a number is the square root of its square root.
In other words, quartic root of x can be expressed as ![\[\sqrt{\sqrt{x}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B%5Csqrt%7Bx%7D%7D%5C%5D)
This can be expressed equivalently as ![\[\sqrt{x^{\frac{1}{2}}}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7Bx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%5C%5D)
![\[={x^{\frac{1}{4}}}\]](https://tex.z-dn.net/?f=%5C%5B%3D%7Bx%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5C%5D)
Answer:
2200 Square Yards
Step-by-step explanation:
Dimension of the Youth Soccer Field = 110 yards long and 60 yards wide.
- Therefore Area of the Youth Soccer Field = 110 X 60 =6600 Square Yards
Dimension of the professional soccer field =110 yards long and 80 yards wide.
- Area of the professional soccer field = 110 X 80 =8800 Square Yards
The difference in their Area = 8800-6600=2200 Square Yards
Therefore, the professional soccer field has an area of 2200 Square Yards more than the youth soccer field.
Answer:
slope = 3/2, y-interecept = -.5
Step-by-step explanation:
To find a perpendicular line, just take the current slope (-2/3) and find the opposite reciprocal of 3/2. Then, you can just slowly find your way to the y-intercept through subtraction (or division if you'd rather, both are much quicker than the way most textbooks would tell you - remember, in math, there is no one set way!)
Answer:
So the numbers are 12 and -3.
Step-by-step explanation:
In order to solve this problem we will attribute variables to the numbers, the first one will be "x" and the second one will be "y". From the first sentence we know that the subtraction of the two numbers is equal to 15, so we have:
x - y = 15
Then the problem states that one-third of the sum of the number is equal to one quarter of the first number, so we have:
(1/3)*(x+y) = x/4
Since we now have two equations and two variables we can solve for x and y. From the first equation we have:
y = x - 15
Using this expression for the value of y in the second equation:
(1/3)*(x + x - 15) = x/4
(1/3)*(2*x - 15) = x/4
2*x - 15 = 3*x/4
2*x - 3*x/4 = 15
(8*x - 3*x)/4 = 15
5*x/4 = 15
5*x = 60
x = 60/5 = 12
y = x - 15 = 12 - 15 = -3
So the numbers are 12 and -3.
