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3 years ago

What is 8,731 divided by 2

Mathematics

1 answer:

lukranit [14]3 years ago

3 0

Answer:

4365.5 or 4365 1/2

Step-by-step explanation:

When you divide 8731 by 2 you will get a decimal.

But you will also get a fraction which is 4365 1/2.

Now you will have to answer with the for that best fits your problem.

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Dennis is joining an online video game service. He will pay $25.50 to purchase each game plus a one-time foe of $4500 to join

insens350 [35]

Answer:

I am pretty certian it is A

Step-by-step explanation:

You add the x to 25.50 because it is unknown how many games he will buy and add the one time pay of 4,500 to enter the service/company

So it is y= 25.50x + 45

6 0

3 years ago

Read 2 more answers

A group of students measured the lengths of their shoes. The lengths are listed in the table. Use the table to locate the incorr

Maru [420]

I think the incorrect data is the second x to the left.

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2 years ago

What is the solution, vertex, and y-intercept of the graph? Please answer ASAP.

inna [77]

Graph is accurate enuf so that you can determine immed that the vertex / minimum is at (3,-4) and that the y-intercept is at (0,5).

If by "solutions" you mean "roots," the roots are {1, 5} (where y=0).

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3 years ago

How to solve this derivative. f(x)={ln(3x)}^2x with steps...

AysviL [449]

Rewrite f(x) as a nested exponential-logarithm expression :

$\left(\ln(3x)\right)^{2x} = \exp\left(\ln\left(\ln(3x)\right)^{2x}\right)$

(where $\exp(x) = e^x$ )

One of the properties of logarithms lets us drop the exponent as a coefficient:

$\exp\left(\ln\left(\ln(3x)\right)^{2x}\right) = \exp\left(2x\ln\left(\ln(3x)\right)\right)$

Now, by the chain rule, we have

$f(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \implies \\\\ f'(x) = \left(\exp\left(2x\ln\left(\ln(3x)\right)\right)\right)' \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2x\ln\left(\ln(3x)\right)\right)'$

By the product rule,

$f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left( (2x)' \ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left( 2\ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)' \right)$

By the chain rule again,

$f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + 2x \cdot \dfrac1{\ln(3x)} \cdot \left(\ln(3x)\right)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2x}{\ln(3x)} \cdot \dfrac1{3x} \cdot (3x)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{3\ln(3x)} \cdot 3 \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)$

Then simplify this to

$f'(x) = \boxed{\left(\ln(3x)\right)^{2x} \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)}$

8 0

3 years ago

Can you please help me

Tanya [424]

Answer:

Step-by-step explanation:

5 0

3 years ago