27. MODELING WITH MATHEMATICS Write and solve an

At what point on the parabola y = 3x^2 + 2x is the tangent line parallel to the line<br> y = 10x −2?

oksian1 [2.3K]

Answer:

( $\frac{4}{3}$ , 8 )

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 10x - 2 ← is in slope- intercept form

with slope m = 10

Parallel lines have equal slopes

then the tangent to the parabola with a slope of 10 is required.

the slope of the tangent at any point on the parabola is $\frac{dy}{dx}$

differentiate each term using the power rule

$\frac{d}{dx}$ (a $x^{n}$ ) = na $x^{n-1}$ , then

$\frac{dy}{dx}$ = 6x + 2

equating this to 10 gives

6x + 2 = 10 ( subtract 2 from both sides )

6x = 8 ( divide both sides by 6 )

x = $\frac{8}{6}$ = $\frac{4}{3}$

substitute this value into the equation of the parabola for corresponding y- coordinate.

y = 3( $\frac{4}{3}$ )² + 2

= (3 × $\frac{16}{9}$ ) + 2

= $\frac{16}{3}$ + $\frac{8}{3}$

= $\frac{24}{3}$

= 8

the point on the parabola with tangent parallel to y = 10x - 2 is ( $\frac{4}{3}$ , 8 )

3 0

2 years ago

A fleece top costs $34.00. It is on sale for one over four off. What is the sale price?

jarptica [38.1K]

If im correct it will be 8.5

8 0

4 years ago

Worth 80 points how much wood would a wood chuck chuck if a wood chuck could chuck wood!?!? I need to know a legit number and ho

DanielleElmas [232]

Answer:

31 chucks

Step-by-step explanation:

7 0

3 years ago

It is possible to get 2 solutions when the system of equations is: (check all that apply)

SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as $x^2+ y^2 = 1$ ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

$x^2 + x^2 = 1\\2x^2 = 1\\$

$x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$ so Y = $+\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$

so the two solution are ( $(\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} }$ )

A system of the equation of a parabola and a linear equation

Let equation of Parabola be $y^2 = x$

and linear equation y = x

substitute

$x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1$

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0

3 years ago

Which compound inequality is equivalent to the absolute value inequality |bl> 6?

dimulka [17.4K]

Answer:

b > -6 or b < 6

Step-by-step explanation:

The absolute value operator always returns a positive number, with |b| = b if b > 0, and |b| = -b if b 0. With this in mind, consider the following inequality:

|b| > 6

Because of the absolute value operator, this is valid for b values larger than 6 and less than -6. As a result, the compound inequality that this circumstance illustrates is:

b< -6 or b > 6

8 0

2 years ago