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babunello [35]
3 years ago
8

Find the equation in the slope intercept form of a line that goes through the point (2,-6) and has the slope of (-1/3)

Mathematics
1 answer:
Llana [10]3 years ago
8 0

Answer:

y = -1/3x - 5 1/3

Step-by-step explanation:

Slope Intercept =

y=mx + b

Substitute the Slope

y= -1/3x + b

Substitute x and y from the point into the equation

-6 = -1/3(2) + b

-6 = -2/3 +b

Isolate the b with the addition property of equality

-5 1/3 = b

Substitute all variables

y = -1/3x - 5 1/3

You might be interested in
Which set of ordered pairs represents y as a function of x?
ikadub [295]

Answer:

{(1, 2), (2, -3), (3, 4), (4, -5)}

Explanation:

The <u>domain</u>, or <u>x-value</u><u>,</u> isn't repeated, while it is in the other answer choices, making the others <u>non</u><u>-</u><u>f</u><u>unctions</u>.

8 0
3 years ago
Mandy and Jeff start running around the track in the same direction at the same time. Mandy runs one lap in 2 minutes and 30 sec
Savatey [412]

Answer:

At 8:52:30 am they will be side-by-side again

Step-by-step explanation:

Let s be the distance ran in one 1 lap.

Here Jeff runs one extra lap compared to Mandy for coming side by side again.

Mandy runs one lap in 2 minutes and 30 seconds = 150 s

Speed of Mandy, =\frac{s}{150}

Jeff runs one lap in 2 minutes and 15 seconds = 135 s

Speed of Jeff, =\frac{s}{135}

Let t be the time when Jeff run one extra lap,

That is

              t\times \frac{s}{135}-t\times \frac{s}{150}=s\\\\t\left ( \frac{1}{135}-\frac{1}{150}\right )=1\\\\t\times \frac{15}{135\times 150}=1\\\\t=1350s

So after 1350 seconds Jeff comes side by side to Mandy,

They both start at 8:30 am

             1350 s = 22.5 minutes = 22 minutes 30 seconds

          Time = 8:52:30 am

3 0
3 years ago
Lin runs 12 laps around a track in 15 minutes.
nalin [4]

Answer:

1.25

Step-by-step explanation:

15/12

5 0
3 years ago
A man standing near a radio station antenna observes that the angle of elevation to the top of the antenna is 64 He then walks 6
larisa86 [58]

The height of the radio station antenna is approximately 116 feet to the nearest foot.

From the diagram in the attached image

h=\text{the height of the radio station antenna}\\x=\text{the distance from the foot of the radio station antenna to where the man stood at first}

we now have the following relationships

tan64^\circ=\frac{h}{x}\\\\\implies x=\frac{h}{tan64^\circ}

and

tan43^\circ=\frac{h}{68+x}\\\\\implies x=\frac{h}{tan43^\circ}-68

we can equate the two relationships to eliminate x.

\frac{h}{tan64^\circ}=\frac{h}{tan43^\circ}-68

solving for the height of the radio station antenna, h, we get

h=\frac{68\times tan43^\circ \times tan64^\circ}{tan64^\circ -tan43^\circ}\approx 116ft\text{ (to the nearest foot)}

Learn more about angle of elevation here: brainly.com/question/12483071

5 0
2 years ago
Bradley's shoe length is 17 cm long. Which list shows the dinosaur skeletons that were more than 320 centimeters long?
Likurg_2 [28]
Wouldn't that be 320x17
4 0
4 years ago
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