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3 years ago

6

Reuben bought n packs of pencils, each pack had 15 pencils, write an equesion to represent the total number of penciles p that r

euben baught

1 answer:

zimovet [89]3 years ago

5 0

P=15n. Hope that helps :)

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At a sale, books are sold at $90.75 each, which is 75 percent of the original price. What is the original price

lions [1.4K]

$\frac{75}{100} = \frac{90.75}{x} \\ x = \frac{90.75 \times 100}{75} = \frac{9075}{75} = 121$
the answer is 121

6 0

3 years ago

If the height is 24, solve for x. h=-16x^2+8x+48

disa [49]

Answer:

x=

32

7+

3121

,

32

7−

3121

Step-by-step explanation:

h+16^2-8x-48=0

-7x+16x^2-48=0

x=

32

7+

3121

,

32

7−

3121

8 0

3 years ago

Which point would be a solution to the system of linear inequalities shown below? y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1 y&g

Sauron [17]

Answer:

$x < \frac{20}{17}$ and $y \ge \frac{-5}{17}$

Step-by-step explanation:

Given

$y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1$

Required

Find x and y

In the second equation. Assume that:

$y = \frac{3}{5}x - 1\\$

Substitute $y = \frac{3}{5}x - 1$ in the first equation

$y > 4x - 5$

$\frac{3}{5}x - 1 > 4x - 5$

Collect like terms

$\frac{3}{5}x - 4x > - 5 + 1$

$\frac{3}{5}x - 4x > -4$

Multiply through by 5

$3x - 20x > -20$

$-17x > -20$

Solve for x

$x < \frac{20}{17}$

Substitute this value of x in $y \ge \frac{3}{5}x - 1$

$y \ge \frac{3}{5}*\frac{20}{17} - 1$

$y \ge \frac{3}{1}*\frac{4}{17} - 1$

$y \ge \frac{12}{17} - 1$

$y \ge \frac{12- 17}{17}$

$y \ge \frac{-5}{17}$

3 0

3 years ago

Email used a total of 7 1half

Gala2k [10]

13 - 5 5/6
= 12 6/6 - 5 5/6
= 7 1/6

hope it helps

7 0

3 years ago

The numerical value of the quantities expressed by the numbers and letters on the left side of the equation (equal sign) is equa

pashok25 [27]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the question, the choices are missing that why it correct can be defined as follows:

The correct choice is "What else the equivalent (=) sign indicates on both sides of every equation".

6 0

3 years ago