Hello :
find : g(x) if <span> f(g(x))=3x-7 and f(x)=1/3x2
</span> f(g(x)) = 1/3(g(x))2 = 3x-7
solve : 1/3(g(x))2 = 3x-7
(g(x))2 = 9x-21
g(x) = <span>√(9x-21)</span>
D
5 + 29 = 34/2 = 17
7 - 15 = -8/2 = -4
(17,-4)
Answer:
2 to the power of one sixth
Step-by-step explanation:
Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:
![\sqrt[n]{x} = {x}^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D%20)
So you can rewrite the given fraction as

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

Since

the answer is
![{2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B6%7D%20%7D%20%20%5C%3A%20or%20%5C%3A%20%20%5Csqrt%5B6%5D%7B2%7D%20)
Answer:
y=3/2x-3/2
Step-by-step explanation:
another way to name 1/4 is a quarter because 1/4 of 100 is 25 %, so that's why it is called a quarter.
hopefully this helps you :)