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inysia [295]
3 years ago
8

At the beginning of this month, the balance of Vance's checking account was $697.96. So far this month, he has received a payche

ck via direct deposit of $962.88, been charged a monthly service fee from his bank of $25.00, used a debit card linked to his account to make a purchase of $83.12, written a check for $138.83 that has already been deposited, and deposited a check written to him for $71.17. What is the current balance of Vance's checking account?
Mathematics
2 answers:
laila [671]3 years ago
6 0
His total account will have 1485.06 in it after everything is said and done.
WINSTONCH [101]3 years ago
4 0

Answer:

The current balance of Vance's checking account is $1485.06.

Step-by-step explanation:

Vance's checking account balance was $697.96

He has received a paycheck via direct deposit of $962.88

After receiving a paycheck his new account balance will be :

$697.96+$962.88 = $1660.84

He has been charged a monthly service fee from his bank of $25.00

So, amount $25.00 will be deducted from his account . So, new balance will be : $1660.84 - $25.00 =  $1635.84.

Now, he made  a purchase of $83.12 using his debit card . So, deduction of this amount will be done from the account .

So, new balance will be : $1635.84-$83.12 = $1552.72

He written a check of amount $138.83 . so  deduction of this amount will be done from the account .

So, new balance will be :$1552.72-$138.83= $1413.89

Now, he deposited a check written to him .of amount $71.17. so, addition of this amount will be done .

So, the new balance will be $1413.89+$71.17=$1485.06.

Thus , The current balance of Vance's checking account is $1485.06.

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Answer:

(a) There are outliers

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Step-by-step explanation:

Given

\sigma = 14.92

\bar x = 22.0

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q_2 = 24.5

q_3 = 33.5

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Solving (a): Check for outliers

This is calculated using:

Lower = Q_1 - (1.5 * IQR) --- lower bound of outlier

Upper = Q_3 +(1.5 * IQR) --- upper bound of outlier

Where

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So, we have:

IQR = 33.5 - 14.5

IQR = 19

The lower bound of outlier becomes

Lower = Q_1 - (1.5 * IQR)

Lower = 14.5 - (1.5 * 19)

Lower = 14.5 - 28.5

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The upper bound of outlier becomes

Upper = Q_3 +(1.5 * IQR)

Upper = 33.5 + 1.5 * 19

Upper = 33.5 + 28.5

Upper = 62

So, we have:

-14 \le x \le 62 --- the range without outlier

Given that:

q_0 = -24  --- This represents the lowest data

q_4 = 64   --- This represents the highest data

-24 and 64 are out of range of -14 \le x \le 62.

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

x and x >62

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Step-by-step explanation:

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Step-by-step explanation:

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Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.

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