Question

One number is 11 less than the other number. If their sum is increased by 8, the result is 71. Find the numbers.

Answer 1

First number = $x$

Second number = $x-11$

$x+x-11+8=71$

$2x-3=71$

$2x=71+3$

$2x=74$

$x=37$

First number = $x=37$

Second number =  $x-11=37-11=26$