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lions [1.4K]
3 years ago
7

What is the equation of the line that passes through the point (-1, -3) and has a slope of -5?

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

<h2>A) y = -5x - 8</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point on a line

We have the slope m = -5, and the point (-1, -3). Substitute:

y-(-3)=-5(x-(-1))\\\\y+3=-5(x+1)

Convert to the slope-intercept form (y = mx + b):

y+3=-5(x+1)          <em>use the distributive property</em>

y+3=-5x-5            <em>subtract 3 from both sides</em>

y=-5x-8

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A socket set is an integral part of a technician's tool box because ____. A. the extension allows easier access to nuts/bolts in
Ann [662]

Answer: C

Explanation:

. there are multiple sockets that can be interchanged easily to accommodate many different size nuts and bolts

8 0
3 years ago
Please help me with this.
JulijaS [17]

The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]

<h3>How to determine the range of speed associate to desired gas mileages</h3>

In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:

g = 10 + 0.7 · v - 0.01 · v²      (1)

An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].

To learn more on quadratic functions: brainly.com/question/5975436

#SPJ1

3 0
2 years ago
Tim,Griff and Kay baked chocolate for Kay s birthday party.Tim baked 3 times as many as Kay.Griff baked half as many as Tim.Alto
lianna [129]
Answer: 48

------------------------------------------------------------------------------
Define the number of cakes they baked in term of x
------------------------------------------------------------------------------
Let the number of cakes Kay baked be x

Kay = x
Tim = 3x                ← Tim baked 3 times as many as Kay
Griff = 1.5x            ← Griff baked 1/2 as many as Tim

------------------------------------------------------------------------------
Construct the equation and solve for x
------------------------------------------------------------------------------
The total number of cakes baked was 88.

x + 3x + 1.5x = 88        ← Combine like terms
5.5 x = 88                     ← Divide by 5.5
÷5.5    ÷5.5
x = 16

------------------------------------------------------------------------------
Find the number of cakes each baked
------------------------------------------------------------------------------
Kay = x = 16
TIm = 3x = 16 x 3 = 48
Griff = 1.5x = 1.5(16) = 24

------------------------------------------------------------------------------
Answer: Tim baked 48 cakes.
------------------------------------------------------------------------------
3 0
3 years ago
Everyone needs to get off of social and help us -_-
JulsSmile [24]
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16

(x^2+10x+16)(x+k)=x^3+9x^2+6x-16

x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16

kx^2+10kx+16k=-x^2-10x-16

k(x^2+10x+16)=-x^2-10x-16

k=(-x^2-10x-16)/(x^2+10x+16)

k=-1

so the width is (x-1)




7 0
3 years ago
Please help me thank you!!
AURORKA [14]
Emma completed the problem correctly i believe
5 0
3 years ago
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