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3 years ago

What is the equation of the line that passes through the point (-1, -3) and has a slope of -5?

Mathematics

1 answer:

spin [16.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

We have the slope m = -5, and the point (-1, -3). Substitute:

$y-(-3)=-5(x-(-1))\\\\y+3=-5(x+1)$

Convert to the slope-intercept form (y = mx + b):

$y+3=-5(x+1)$ use the distributive property

$y+3=-5x-5$ subtract 3 from both sides

$y=-5x-8$

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