What is the term a8 of the sequence {an} if an equalsa) 2n−1?b) 7?c) 1 + (−1)n?d) −(−2)n?
1 answer:
The correct question in the attached figure
case A) an=2<span>^(n-1)
for n=8
a8=2</span>^(8-1)-----> a8=2<span>^7----> a8=128
the answer case A) is
a8=128
case B) an=7
then for n=8
a8=7
the answer case B) is
a8=7
case C) an=1+(-1)</span><span>^n
for n=8
a8=1+(-1)</span><span>^8----> a8=1+1----> a8=2
the answer case C) is
a8=2
case D)an=-(-2)</span><span>^n
for n=8
a8=-(-2)</span><span>^8----> a8=-256
the answer case D) is
a8=-256</span>
case A) an=2<span>^(n-1)
for n=8
a8=2</span>^(8-1)-----> a8=2<span>^7----> a8=128
the answer case A) is
a8=128
case B) an=7
then for n=8
a8=7
the answer case B) is
a8=7
case C) an=1+(-1)</span><span>^n
for n=8
a8=1+(-1)</span><span>^8----> a8=1+1----> a8=2
the answer case C) is
a8=2
case D)an=-(-2)</span><span>^n
for n=8
a8=-(-2)</span><span>^8----> a8=-256
the answer case D) is
a8=-256</span>
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