Say that you start from a number . Then, you subtract and from , which means that the expression is
If we want this expression to be negative, we have
So, in order for the expression to be negative, the two numbers we are subtracting, combined, must be more than the starting number.
For example, if we start from 10 and we subtract 4 and then 8, we have
which is negative, because 4 and 8 combined are more than 10
Consecutive means in order, so like 1,2,3,4... or 14,15,16,17...
consecutive even means 2,4,6,...
now, first you define some variables
let "a1" be the first positive even integer
well, you could define a2,a3,and a4 to be the next consecutive even integers but you actually dont need to
because the next consecutive even integer is
a1+2
the 3rd is
a1+2+2
and the 4th is
a1+2+2+2=a1+6
now, looking at the problem it states the "third" times the "fourth" is equal to 21 times the "first"
putting it into equation form
(a1+4)* (a1+6)= 21*a1
solve for a1, and then it should be easy to determine the rest of the positive consecutive even integers
Answer:
<u><em>Ten Thousands or 60,000</em></u>
Step-by-step explanation:
D. Icosahedron
<span>In geometry, an icosahedron is a polyhedron with 20 faces. </span>
I gotchu
To solve for x-intercepts, y must be 0.
3x - 2(0) - 16 = 0
3x - 16 = 0
3x = 16
x = 16/3
X intercepts are (,0)