C²=a²+b²-2·a·b·cos(C)
c²=(1.5)² + (0.5) -2 ·(l·5) ·(0.5) ·cos(120°)
c²= 3.25
c= √3.25
c=1.802775638
To nearest tenth, c=1.8
A=16 and b=63
So we have to use the Pythagoras theorem for this and that is:
a^2+ b^2 = c^2
And we want to find c , which is the long side of the triangle so..
16^2+ 63^2= 4225
So c^2 =4225
c= square root of 4225
C= 65
Answer:
2 meters
Step-by-step explanation:
Given

The question is incomplete as the picture of the tent is not attached.
However, I will use the attached figure to answer the question.
From the attachment, we have:
--- base of the tent
--- length of the tent
Required
Determine the height of the tent
The volume of the tent is:

Where h is the required height.
So, we have:



Make h the subject


<em>The height of the tent is 2m</em>
Standard form of a line is Y=mX+b
where m is slope
4x+2y=-6
2y=-4x-6
y=- 2x - 6
m= - 2 and y intercept is b=-6