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4 years ago

Academic integrity can be applied to all subject areas. Please select the best answer from the choices provided T F

SAT

2 answers:

Misha Larkins [42]4 years ago

7 0

The correct answer is true.

Hope this helps.

SSSSS [86.1K]4 years ago

4 0

Answer:

Explanation:

No explanation needed. Academic dishonesty is unacceptable under any circumstances.

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B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len

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Answer:

The additional words is $2^n$

Explanation:

Given

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Required

Determine the additional words; i.e. $B(n + 1) - B(n)$

From the given parameters, we have that;

B is a function of n

Such that;

$B(n) = 2^n$

To calculate $B(n+1)$ , we simply substitute n + 1 for n

$B(n) = 2^n$

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Applying laws of indices

$B(n + 1) = 2^{n} * 2^1$

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Calculating Additional Binary Code;

$B(n + 1) - B(n)$

Substitute values for B(n + 1) and B(n)

$B(n + 1) - B(n) = 2(2^n) - 2^n$

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$B(n + 1) - B(n) = 2(2^n) - 2^n * 1$

Express 1 as $2^0$

$B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0$

Factorize

$B(n + 1) - B(n) = 2^n(2 - 2^0)$

$B(n + 1) - B(n) = 2^n(2 - 1)$

$B(n + 1) - B(n) = 2^n(1)$

$B(n + 1) - B(n) = 2^n$

Hence, the additional words is $2^n$

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