Question

. A fruit company recently released a new applesauce. By the end of its first​ year, profits on this product amounted to $24,700.  The anticipated profit for the end of the fourth year is $67,900.  After the first​ year, the ratio of change in time to change in profit is constant. Let x be years and P be profit in dollars.
P(x)=
2. Find an equation of the line. Write the equation using function notation.
Through (6,−5)​; perpendicular to 4y=x-8
3. Find an equation of the line. Write the equation using function notation.
Through (-3,-8) ; parallel to 2x+3y=5
4. Find the equation of the line
Through (-11,-4) perpendicular to y=15

Answer 1

Answer:

1) P(x) =14400x+10300 2)y=-4x+19 3)$y=\frac{-2x}{3} -14$ 4) x=-11

(Please check the pictures for better understanding)

Step-by-step explanation:

1) Firstly, let's organize the data. Let the dependent variable x be the years, and the Range P(x) the Profit. So arranging these linear functions y=ax+b and plugging the coordinates for each point (1, 24700) and (4, 67900). Goes:

24,700=x+b

67,900=4x +b

1.1)Solving for b, this Linear System of Equation by the Addition Method goes:

$24,700=x+b*(-4)\\67,900=4x+b\\----------\\-98,800=-4x-4b\\67,900=4x+b\\ -----------\\-30900=-3b\\\frac{3b}{3} =\frac{30900}{3}\\ b=10300$

1.2) Now, let's find the slope based on those two points (1, 24700) and (4, 67900) and using the formula to find the slope:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{67900-24700}{4-1}\\ m=\frac{43200}{3}\\ m=14400$

So now we can write this Linear Equation for the Profit:

P(x) =14400x+10300

2) An equation of the line perpendicular to 4y=x-8 has a slope equal to $m_{2}$=-$\frac{-1}{m_{1}}$ the line. In this case, an equation perpendicular to 4y=x-8 .

Rearranging the given equation of the line 4y=x-8 goes:

$y=\frac{x}{4} -\frac{8}{4} \\ y=\frac{x}{4}-2$

2.1) The slope of this new line is equivalent to m=-4 since -4 is opposite inverse value for the slope of its perpendicular line (1/4).

If the line passes through the point (6,-5), then this point already belongs to this line.

Then, we can write.

-5=-4(6)+b

-5=-24+b

-5+24=-24+24+b

b=19

Now we can write the function:

y=-4x+19

3) Firstly, let's rearrange the equation. Into a General Equation of the Line y=ax+b

2x+3y=5

-2x+2x+3y=5-2x

3y=5-2x

$\frac{3y}{3} =\frac{5}{3} -\frac{2x}{3}$

$y=\frac{-2x}{3}+\frac{5}{3}$

3.2) Let's find out b, the linear coefficient by plugging the coordinates of the point (-3,-8).

Also, Parallel lines have the same value for the slope such as $m_{1}=m_{2}$

-8=-3(-2/3)+b

-8=2+b

-8-2=2-2+b

b=-10

Then the equation of this parallel line is:

$y=\frac{-2x}{3} -10$

4) Now on this last question, we have to find an equation of the line through the point (-11,-4)  perpendicular to another line y=15

Suppose the slope of the first line is $m_{1}$ and the value of the slope of its perpendicular is $m_{2}=\frac{-1}{m_{1}}$

y=15 is a horizontal line with slope equals zero, we can rewrite it as y=0x+15.

Then the slope is zero for horizontal lines.

A perpendicular line to a horizontal line is a vertical one.

In addition to this, a vertical line passes through only one point in the x-axis. Then, there is no horizontal variation. This leads the formula of a slope to an undefinition for Real Set.

$m=\frac{y_{2}-y_{1}}{0}$

The only perpendicular line which passes through the point (-11,-4) to y=15 is the line x=-11.