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Helga [31]
3 years ago
14

What is the common denominator for theses: 5/6, 7/9, 3/5

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0
You are correct

For it to be a common denominator, It must be divisible by all the other denominators.

Out of your options, 90 is the only one that can be factorised with a 6, 9 and 5
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If the police have 9 suspects how many different ways can they select 5 for a lineup
kow [346]
Assuming the order does not matter, you want the number of combinations of 9 things taken 5 at a time.  The combinations can be shown as C(9,5), 9C5.

C(9, 5) =
9/5(9-5) = 
9*8*7*6*5 / 5*4 

The 5 terms cancel. 

9*8*7*6 / 4*3*2 = 
9*7*2 = 
126

The above change is because 4*2 cancels the 8 in the numerator and 6/3 = 2
Therefore, the solution is 126. 
4 0
3 years ago
Casey said that 0.03*1,000 is 3 explain why caseys answer is wrong what mistake do u think he made
Igoryamba
<span>0.03 x 1,000=30! In multiplying decimals, you'll move the decimal's period to the number of zeroes in the multiplier! 1,000 has 3 zeroes. So, it's equal to 30. So basically he was wrong because 0.03 times 1,000 doesn't equal 3 it equals 30. He made the mistake of not moving the decimal point enough.</span>
6 0
3 years ago
Please help me with this
Tamiku [17]

Answer:

20%

hope it helps you

8 0
3 years ago
Jayden just graduated from college and owes $19,400 on his student loans. The
ELEN [110]

Answer:

M=19400(1.5)/1-(1+1.5)-(15x12)

M=28917.50

Then you would round up so it wo9uld be $28,918.

6 0
3 years ago
What is this expression in simplified form? (v22)(5v2)​
elixir [45]

Answer:

5v24

Step-by-step explanation:

(v22)(5v2) = 5v(2+22) = 5v24

3 0
3 years ago
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