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Ksivusya [100]
4 years ago
15

Can someone please help me

Mathematics
1 answer:
Tamiku [17]4 years ago
8 0

Answer: Parrallegram B

Step-by-step explanation:

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A sphere rolls up an inclined plane of inclination angle 30 degree. At the bottom of the incline the center of mass of the spher
Zigmanuir [339]

Answer: The sphere is 0.002548 cm travel up the plane.

Step-by-step explanation:

Since we have given that

Inclination angle = 30°

Translational speed = 0.25 m/s

As we know that

KE=0.5\times lw^2=PE

and

Length of solid sphere is given by

l=\dfrac{2Mr^2}{5}

So, it becomes,

KE=0.5\times \dfrac{2Mr^2}{5}w^2=Mgd\sin \theta

And 0.25\ m/sv=rw

So, it becomes,

1\times (0.25)^2=5\times d\times 9.81\times \sin 30^\circ\\\\0.0625=49.05d\times \dfrac{1}{2}\\\\\dfrac{0.125}{49.05}=d\\\\d=0.002548

Hence, the sphere is 0.002548 cm travel up the plane.

5 0
4 years ago
Y varies inversely as x, and y = 50 when x = 10. What is the value of y when x = 20? 100
Blizzard [7]
100 because of the system

have a good day
8 0
3 years ago
Read 2 more answers
Please help me real quick ​
Eddi Din [679]

Answer:

x= 7

Step-by-step explanation:

11x-2 = 75

11(7) - 2

77 - 2 = 75

x= 7

3 0
3 years ago
The failure of a circuit board interrupts work that utilizes a computing system until a new board is delivered. The delivery tim
Hatshy [7]

Answer:

The expected cost is 152

Step-by-step explanation:

Recall that since Y is uniformly distributed over the interval [1,5] we have the following probability density function for Y

f_Y(y ) = \frac{1}{5-1} = \frac{1}{4} if 1\leq y \leq 5 and 0 othewise. (To check this is the pdf, check the definition of an uniform random variable)

Recall that, by definition  

E(Y^k) = \int_{-\infty}^{\infty} y^kf_Y(y)dy

Also, we are given that C = 50+3Y+9Y^2. Recall the following properties of the expected value. If X,Y are random variables, then

E(a+bX+cY) = a+bE(X)+cE(Y)

Then, using this property we have that E[C] = 50+3E[Y]+ 9E[Y^2].

Thus, we must calculate E[Y] and E[Y^2].

Using the definition, we get that

E[Y] = \int_{1}^{5}\frac{y}{4} dy =\frac{1}{4}\left\frac{y^2}{2}\right|_{1}^{5} = \frac{25}{8}-\frac{1}{8} = 3

E[Y^2] = \int_{1}^{5}\frac{y^2}{4} dy =\frac{1}{4}\left\frac{y^3}{3}\right|_{1}^{5} = \frac{125}{12}-\frac{1}{12} = \frac{31}{3}

Then

E(C) = 50 + 3\cdot 3 + 9 \cdot \frac{31}{3} = 152

5 0
3 years ago
Complete the equation to show two equivalent expressions.
Anuta_ua [19.1K]
The answer is (g-7)(g+3)
7 0
4 years ago
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