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djyliett [7]
3 years ago
15

Dimtry bought a pair of pants at the discounted price of $30. The original price of the pants was $40. What was the percent of t

he discount? PLEASE EXPLAIN TO ME HOW YOU GOT YOUR ANSWER
Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

Say we start from the beginning with $40. If the pants are discounted but we don't know the percent discount, then we need a variable, x:

40 - x% * 40 = 30

The total is 40. When we take a discount off of 40, we are taking a percent of 40 and subtracting that from 40. From the problem, this should be 30. Thus, the equation above.

Add x%*40 to both sides and subtract 30 from both sides:

x%*40 = 10

Divide by 40:

x% = 1/4 = 0.25

Multiply each side by 100:

x = 25

The answer is 25%.

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Which two are equivalent?
never [62]

Answer:

Expression I and IV

Step-by-step explanation:

Expression I simplified :

  • 3n + 7 + n + 4n
  • 8n + 7
  • Expression I = Expression IV
7 0
2 years ago
Help on number 6 i don't understand how to do it and i got corrections so i need help to do them.
Mademuasel [1]
The answer #6 is j. 100. He uses the treadmill for 40% so that means 60% of his exercise is not on the treadmill. 

40%= 40 mins 
60%= 60 mins
 total: 100%= 100 mins.
Hope this helps!
8 0
3 years ago
Read 2 more answers
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
What is the discount and sale price of a $300 item that has been discounted 10%?
Paha777 [63]
270 I think if not my bad
7 0
3 years ago
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Is KLMN below a rectangle?
8_murik_8 [283]
Should be C right? A rectangle demands that the diagonals are congruent
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