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butalik [34]
3 years ago
7

Find the area of the rhombus leave the answer in simplest radical form

Mathematics
1 answer:
kotykmax [81]3 years ago
3 0
I just really need to answer a question to be able to ask. sorry!!
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5/12 expressed as a decimal fraction is? (Round to the nearest thousandths)
Makovka662 [10]

Answer:

5/12 = 0.416666667 if you round up to the nearest thousandths it would be 0.417

7 0
3 years ago
Read 2 more answers
The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of
lora16 [44]

Answer:

The dimension of the sandbox is (2x+1) by (x - 3)

Step-by-step explanation:

It seems the complete question will be:

The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of x.

Step-by-step explanation:

From the question, the given expression is 2X^2-5x-3. This can be rewritten as

2x^{2} -5x-3

If the area of the sandbox in park is represented by this expression, then the dimensions of the sandbox will be the product of the factors. To determine the factors, we will factorize the given quadratic expression.

Factorizing the expression 2x^{2} -5x-3, we get

2x^{2} -6x+x-3

2x(x-3)+1(x-3)

(2x+1)(x-3)

Hence, the dimension of the sandbox is (2x+1) by (x - 3)

6 0
3 years ago
Please help thanks in advance
Over [174]
\frac{2(5)^2}{5} +5(100-15(5))\\\\  \frac{2*25}{5}+5(100-15(5))\\\\ \frac{50}{5}+5(100-15(5))\\\\ 10+5(100-15(5))\\\\ 10+5(100-75)\\\\ 10+5(25)\\\\ 10+125\\\\ 135\\\\ Final answer: 135\\
8 0
3 years ago
Use the following data set to answer numbers 1 - 4.
alukav5142 [94]

Answer:

1. 13+18+13+14+13+16+14+21+13

= 145/9

=16.11

2. Range =145

3. Mode =13

4. Median =14

Step-by-step explanation:

6 0
2 years ago
A high school basketball coach is selecting his team. The minimum and maximum height requirements are as follows:
daser333 [38]

Answer:

B. About 2% of the boys are eligible to be a small forward on the team

Step-by-step explanation:

Recall : 1 feets = 12 inches

Point guard = 6’2" – 6’6" tall = 74 - 78 inches

Mean = 70 ; Standard deviation = 4

Z = (x - mean) / standard

P(x < 74) = (74 - 70) / 4 = 1

P(x < 78) = (78 - 70) / 4 = 2

0.97725 - 0.84134 = 0.13591

Small forward : 6'6" = 78 inches

P(x ≥ 78) = (78 - 70) / 4 = 2

P(z ≥ 2) = 0.02275 = 2.275% about 2%

Centre : 6'8" = 80

P(x ≥ 80) = (80 - 70) / 4 = 2.5

P(z ≥ 2.5) = 0.0062097 = 0.62%

8 0
3 years ago
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