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Elena L [17]
3 years ago
9

How to find the volume of a cylinder ​

Mathematics
2 answers:
Kryger [21]3 years ago
5 0

Cylinder volume formula:

V=\pi r^2h

This is just the area of the circle (\pi r^2) multiplied by the height of the cylinder.

katrin2010 [14]3 years ago
5 0

Answer:

V=^2h

Step-by-step explanation:

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When the equation is graphed is it linear or nonlinear ??
Keith_Richards [23]

Answer:

Nonlinear

Step-by-step explanation:

This is nonlinear because its parent function is y = x^{2}. The parent function of a linear equation is y = x.

I hope this helps :))

8 0
3 years ago
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Wat is 10,000 more than 6,310
ziro4ka [17]
To find 10,000 more than 6,310, you add; so the answer is 16,310
3 0
3 years ago
Zach wants to have a flower bed in his backyard he measures the area of the flower bed to be 10 square feet the actual measureme
MrRissso [65]
The answer would be- 6%
4 0
3 years ago
Hi can someone help me on this please? I am having trouble understanding this one :) thx
fomenos

Answer:

I would say its the bottom one

Step-by-step explanation:

The top one goes to five while the bottom only goes to four, plus you cant have a negative amount of people you can only have from 0 to infinity amount of people.

4 0
3 years ago
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Use algebra to find the point at which the line h(x)=−(3/5)x+(7/5) intersects the line k(x)=(−8/3)x+(404/45).
Inga [223]

Answer: the point (3.667, 0.8)

Step-by-step explanation:

We want to find the point at which the lines:

h(x) = -(3/5)*x + (7/5)

and

k(x) = (-8/3)*x + (404/45)

If the lines intersect, then we must have:

h(x) = k(x)

if we write the functions we get:

-(3/5)*x + (7/5) = (-8/3)*x + (404/45)

Now we need to solve this for x.

-(3/5)*x + (8/3)*x = (404/45) - (7/5)

(8/3 - 3/5)*x = 404/45 - 63/45 = 341/45

(40/15 - 9/15)*x = 341/45

(31/15)*x = 341/45

x = (341/45)*(15/31) = 3.667

Now we can input this value of x in the functions to get the output.

h(3.667) = -(3/5)*3.667 + 7/5 = -0.8

Then the point where our points intersect is the point (3.667, 0.8)

4 0
3 years ago
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