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WARRIOR [948]
3 years ago
13

I need help ASAP!!!!!!!!!!!??

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0
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nexus9112 [7]
The answer is -19!!!
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3 years ago
Simplify the expression -4x^2(3x − 7).
satela [25.4K]

Answer:

Step-by-step explanation:

Simplify the expression -4x^2(3x − 7).

A. -12x^3 + 28

<h2>B. -12x^3 + 28x^2<= your answer</h2>

C. -12x^3 − 28

D. -12x^3 − 28x^2

5 0
3 years ago
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Write a rational function with no vertical asymptotes and no holes. Please explain.
Ksju [112]

ANSWER

f(x) =  \frac{ {x}^{2} }{ {x}^{2} + 1 }

EXPLANATION

We write the function such that both the numerator and the denominator are prime.

An example of a rational function with no vertical asymptotes and no holes is

f(x) =  \frac{ {x}^{2} }{ {x}^{2} + 1 }

For the above rational function, the denominator is never zero, so there are no vertical asymptotes.

Also the highest common factor for the numerator and the denominator is 1 so there are no holes.

4 0
3 years ago
Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?
algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.


Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.


Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.


So, the coordinates of the endpoint are T = (5,-13)


If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.


We have G = (-3, 5) and T = (x_T,y_T). The midpoint is computed as


A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)


So, you have the equations


\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4


Multply both equations by 2 to get


-3+x_T = 2,\qquad 5+y_T = -8


Move the constants to the right hand sides to get


x_T = 5,\qquad y_T = -13

8 0
3 years ago
Hey I'm back anyone remembers me?​
frozen [14]
No I do not remember you but it’s nice to meet you I suppose.
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