Ok, on the table is says f(x), in the question is says f where x is -2, so go down the f(x) side of the table and find the number it correlates with, which is 3 :)
Answer:
Step-by-step explanation:
The answer to the question is a. 60°
120 groups <span>(10*9*8/3*2*1=120) </span>of 3 (k) operators are possible to make from the 10 (n) qualified employees. This problem can be solved using the combination formula in mathematics which is to find the possible number of combination (group of operator) from a set of choices. (Formula : n*(n-1)*...* (n-k+1)/ k!).
A. G(F(x)) = G (sqrt x + 1) = 3 (sqrt x + 1)