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torisob [31]
3 years ago
13

What is the x intercept for y=(2x(x-3))/(x-1). ?

Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Answer:

( 0,0) and (3,0)

Step-by-step explanation:

y=(2x(x-3))/(x-1)

Set y = 0

0 =(2x(x-3))/(x-1)

Multiply each side by x-1, which makes x not equal to 1

0 =(2x(x-3))

Using the zero product property

2x=0  x-3 =0

x=0   x= 3

The x intercepts are x=0   x= 3

( 0,0) and (3,0)

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Determine whether each of these functions from {a, b, c, d} to itself is one-to-one.
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Answer:

Only function (a) is one-to-one.

Step-by-step explanation:

If every element of the range of the function corresponds to exactly one element of the domain, then the function is called one-to-one.

The elements of a function are

A = {a,b,c,d}

We need to check whether f\rightarrow A\times A is one to one or not.

(a)

f (a) = b, f (b) = a, f (c) = c, f (d) = d

Here, for each value of x, there exist exactly one value of y.

Therefore, this function is one-to-one.

(b)

f (a) = b, f (b) = b, f (c) = d, f (d) = c

Here, the value of function is b for x=a and x=b. For two domains the functions has same range.

Therefore, this function is not one-to-one.

(c)

f (a) = d, f (b) = b, f (c) = c, f (d) = d

Here, the value of function is d for x=a and x=d. For two domains the functions has same range.

Therefore, this function is not one-to-one.

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3 years ago
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Explanation:

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