Answer:
![\displaystyle d = 2\sqrt{10}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%202%5Csqrt%7B10%7D)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra II</u>
- Distance Formula:
![\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points from graph.</em>
Point R(-2, -4)
Point S(-8, -6)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points[DF]:
![\displaystyle d = \sqrt{(-8+2)^2+(-6+4)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%28-8%2B2%29%5E2%2B%28-6%2B4%29%5E2%7D)
- (Parenthesis) Add:
![\displaystyle d = \sqrt{(-6)^2+(-2)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%28-6%29%5E2%2B%28-2%29%5E2%7D)
- [√Radical] Exponents:
![\displaystyle d = \sqrt{36+4}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B36%2B4%7D)
- [√Radical] Add:
![\displaystyle d = \sqrt{40}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B40%7D)
- [√Radical] Simplify:
![\displaystyle d = 2\sqrt{10}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%202%5Csqrt%7B10%7D)
Answer:
B.
Step-by-step explanation:
If you calculate the sum of both you get:
5x + 2x + 4y - 7y = 24 + 26
7x - 3y = 50, which is B
If you graduated in 2010 then you started high school in....
2010-4 years (university education years) - (3 high school years)= 2003
you started high school education in 2003
(7-(-1))^2 +(-2)^2=60 Answer should be B