What was the date the declaration of independence signed?

Part B A sales person earned 1375

Furkat [3]

Question:

A salesperson earns commission on the sales that she makes each month.

The salesperson earns a 5% commission on the first $5,000 she has in sales.

The salesperson earns a 7.5% commission on the amount on her sales that are greater than $5,000.

Part A:

This month the salesperson had $8,000 in sales. What amount of commission, in dollars, did she earn?

Part B:

The salesperson earned $1,375 in commission, last month. How much money, in dollars, did she have in sales last month?

Answer:

A) The amount of commission = $575

B) The total sales amount = $20000

Step-by-step explanation:

Given:

Total amount earned = $8,000 in sales

To Find :

The amount of commission, in dollars

Solution:

The commission she earns = Commission 1+ Commission 2----------(1)

Commission 1 = 5% of 5000

Commission 2 = 7.5 % of (8000- 5000}

Finding commission 1:

= 5% of 5000

= $\frac{5}{100} \times 5000$

= $0.05 \times 5000$

= $250 ------------------------------(2)

Finding commission 2:

= 7.5 % of (3000)

= $\frac{7.5}{100}\times 3000$

= $0.075 \times 3000$

= $225----------------------------------(3)

Substituting (2) and (3) in (1)

The commission she earns = $250 + $225 = $575

Given:

Total commission earned = $1375

To Find :

The total sales amount = ?

Solution ;

Let the sales amount be x

Then

1375 = 5% of 5000 + 7.5 % of (x -5000)

$1375 = 0.05 \times 5000 + 0.075 \times (x -5000)$

1375 = 250 + 0.075x - 375

1375 = -125 + 0.075 x

1375 +125 = 0.075 x

1500 = 0.075x

$x = \frac{1500}{0.075}$

x = 20000

The total sales amount is $20000

5 0

3 years ago

PLS HURRY DONT HAVE A LOT OF TIME!!! danny measured a house and its lot and made a scale drawing. the scale he used was 1 inch :

valkas [14]

10 inches because 40/4*1

6 0

2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$