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Vsevolod [243]
3 years ago
9

What is the domain and range on this graph?

Mathematics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

The answer to your question is Domain (-∞, ∞) Range  [-4, ∞)

Step-by-step explanation:

The Domain is the set of all possible values of the independent variable (x).

The Range is the set of all the possible values of the dependent variable when substitute the domain in the function.

On the graph, we find the domain looking at the x-axis

On a graph, we find the range, looking at all the y-axis

In this graph, x has values from -infinite to infinite, then, the domain is (-∞, ∞).

In this graph, y has values from -4 to infinite, then, the range is [-4, ∞)

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Karen raked 3/5 of the yard he yard. Minute raked 1/3 of the amount Karen raked. How much of the yard did Minnie rake
disa [49]
(3/5)(1/3)=1/5 of the yard
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3 years ago
A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

6 0
3 years ago
What’s 7^2+15\7^2 ?
Elis [28]
Decimal: )49.306122)
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3 years ago
Solve the following system of liner equations:
nexus9112 [7]
First we get the value of y in terms of x

We have 2x + y + 9 = 0

We transpose 2x and 9 to the other side so we could get the value of y being:
y = - 2x - 9

Now that we have the value of y we can substitute it to the first equation
6x - 3y + 10 = 0
6x - 3 (-2x - 9) + 10 = 0
Simplifying the inside of the parentheses we would have
6x - (3)(-2x) - (3)(-9) + 10 =0
6x + 6x + 27 + 10 = 0

Combining similar terms we would get
12x + 37 = 0
We transpose 37 to the other side for easier simplification
12x = - 37
We divide both sides by 12 to get the value of x
12x/12 = - 37/12
Since 12/12 is equal to 1 our value of x would be
x = - 37/12
Or simply x = - 3.0833

Now that we know the value of x we can use it to obtain the value of y
y = - 2x - 9
y = - 2(-37/12) - 9
y = 37/6 - 9
y = - 17/6
Or in decimal y = - 2.8333

Final values of x and y would be
x = - 3.0833
y = - 2.8333
3 0
3 years ago
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Which statements are true about the ordered pair (7, 19) and the system of equations?
svp [43]
Explain it more so I can answer it
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2 years ago
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