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ser-zykov [4K]
3 years ago
9

Which ordered pairs are on the line with the equation y+3.5=0.75(x-2)? I will mark brainliest. Thanks!

Mathematics
1 answer:
kogti [31]3 years ago
7 0
I think the answer is (7, 5.5)
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£100 is divided between Fiona, Pip and Sara so that Fiona gets twice as much as Pip, and Pip gets 3 times as much as Sara. How m
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Step-by-step explanation:

if pip gets x

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3.76+​(y-​1/​2)/​2 need help noww homework
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4 0
3 years ago
Which equation is equivalent to f(x)=16x^4-81=0
Talja [164]
I'm pretty sure you are looking for factored forms as an equivalent equation, so here is how you do it. 
This equation would be solved by difference of squares. 16, x^4, and 81 are all perfect squares ( which means that it is a number multiplied by itself, 16 is 4 x4 for example). So the first thing you want to do is recall the formula which is
(a^2 - b^2) = (a - b)*(a + b) 
(16x^4 - 81)= 0
Find the sq. root of 16 which is 4, and of x^4 which is x^2, and 81 which is 9. Now re write it in the (a - b)*(a + b) format. ----> (4x^2 - 9)*(4x^2 + 9) = 0
7 0
3 years ago
Read 2 more answers
solve for a dairy needs 275 gallons of milk containing 5% butterfat. how many gallons each of milk containing 7% butterfat and m
Kazeer [188]
X = gallons of the 7% butterfat milk

y = gallons of the 2% butterfat milk


now, we'll be adding "x" gallons of the 7% one, but we know that, is really "x" gallons, but only 7% of it is butterfat, the rest is water and other subtances.

so, in "x" gallons, how many gallons is butterfat only anyway?  namely, what is 7% of "x"?  well, (7/100) * x, or 0.07x.

likewise, how many gallons of butterfat are in the 2% one?  well, (2/100) * "y" or 0.02y.

we know that, whatever "x" and "y" add up to 275 gallons, thus x + y = 275.

we also know that, the butterfat amounts add up to the same butterfat in the 275 gallons, thus

\bf \begin{array}{lccclll}
&\stackrel{gallons}{amount}&\stackrel{butterfat~\%}{quantity}&\stackrel{butterfat~gallons}{quantity}\\
&------&------&------\\
\textit{7\% butterfat milk}&x&0.07&0.07x\\
\textit{2\% butterfat milk}&y&0.02&0.02y\\
--------&------&------&------\\
mixture&275&0.05&13.75
\end{array}

\bf \begin{cases}
x+y=275\implies \boxed{y}=275-x\\
0.07x+0.02y=13.75\\
----------\\
0.07x+0.02\left( \boxed{275-x} \right)=13.75
\end{cases}
\\\\\\
0.07x-0.02x+5.50=13.75\implies 0.05x=8.25
\\\\\\
x=\cfrac{8.25}{0.05}\implies x=165

how much will it be of the 2% milk?  well, y = 275 - x.
7 0
3 years ago
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