Step-by-step explanation:
x=14-6y/3
substituting x=14-6y/3 into eqn 2
2(14-6y/3)+8y=2
multiplying through by 3
2(14-6y/3)×3 +8y×3=2×3
2(14-6y)+24y=6
28-12y+24y=6
28-12y=6
28-6=12y
22=12y
22/12=y
finding x
2x+8(22/12)=2
2x+44/3=2
2x=2-44/3
x=(-38/3)/2
×=-38/6
Combine like terms. 6y-5y is 1y, which simplifies to y. the equation is y-3=15. y=18 is the answer because you add 3 to 15
Let x be the shorter side, and y be the longer side
There would be 4 fences along the shorter side, and 2 fences along the longer side
4x + 2y = 800
Rewrite in terms of y:
y = 400 − 2x
The area of the rectangular field is
A = x*y
Replace Y with the equation above:
A = x(400 − 2x)
A = − 2x^2 + 400x
The area is a parabola that opens downward, the maximum area would occur at the parabola vertex.
At the vertex
x = −b/2a
= −400/[2(−2)]
= 100
y = 400 −2x
y = 400 -2(100)
y = 400-200
y = 200
The dimension of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.
Answer: 0.023 is twenty-three thousandths written in standard form!
